In the parallelogram, find
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Answer:
[tex]{114}^{o}[/tex]
Step-by-step explanation:
From the question,
[tex] < KLO = {73}^{o} [/tex]
[tex] < MLO={41}^{o} [/tex]
Base on the properties of a parallelogram, KL //JM and JK //ML
So, we can say that, <MLO alternates with <KJO and <KLO alternates with <MJO
Since alternative angles are equal,
[tex] < MLO= < KJO = {41}^{o} [/tex]
[tex] < KLO= < MJO = {73}^{o} [/tex]
In addition
[tex] < MLK= < KJM = < KLO + < MLO [/tex]
[tex] < MLK = {41}^{o} + {73}^{o} = {114}^{o} [/tex]
Therefore, m<KJM=[tex]{114}^{o}[/tex]