Question

A line that passes through the point (x,y), with a y-intercept of b and a slope of m, can be represented by the equation y = mx + b.
A line is drawn on the coordinate plane that passes through the point (10,1) and has a slope of -0.5. The y-intercept of the line is
.

Answer 1

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

$y = mx + b$

Where:

m: It's the slope

b: It is the cut-off point with the y axis.

On the other hand, the pending point equation is given by:

$(y-y_ {0}) = m (x-x_ {0})$

Where:

m: It's the slope

$(x_ {0}, y_ {0}):$It is a point through which the line passes.

According to the data we have:

$(x_ {0}, y_ {0}) :( 10,1)\\m = -0.5$

So:

$(y-1) = - 0.5 (x-10)\\y-1 = -0.5x + 5\\y = -0.5x + 5 + 1\\ = -0.5 + 6$

Answer:

The cut-off point with the "y" axis is 6

Answer 2

Answer:

Step-by-step explanation:

y - 1 = -0.5(x - 10)

y - 1 = -0.5x + 5

y = -0.5x + 6