Question

Which circuits correctly show Ohm's law?

Answer 1

Ohm’s Law:
V = IR
V = battery voltage, I = current, R = resistance

Top-left circuit:
V = 25V, I = 5A, R = 5ohm
25 = 5•5
25 = 25
This circuit is correct.

Top-right circuit:
V = 18V, I = 6A, R = 4ohm
18 = 6•4
18 =/= 24
This circuit is incorrect.

Bottom-left circuit:
V = 56V, I = 7A, R = 8ohm
56 = 7•8
56 = 56
This circuit is correct.

Bottom-right circuit:
V = 20V, I = 5A, R = 4ohm
20 = 5•4
20 = 20
This circuit is correct.

The following circuits are correct: top-left, bottom-left, and bottom-right.

Answer 2

This question involves the concept of Ohm's Law.

Circuit "A(TOP-LEFT), C(BOTTOM-LEFT), D (BOTTOM-RIGHT)" correctly shows Ohm's Law.

According to Ohm's Law:

V = IR

where,

V = Voltage

I = Current

R = Resistance

Now, we will apply this to every circuit to check its validity:

CIRCUIT 'A' (TOP-LEFT):

$25\ V = (5\ A)(5\ \Omega)\\25\ V = 25\ V$

Hence, this shows Ohm's Law correctly.

CIRCUIT 'B' (TOP-RIGHT):

$18\ V=(6\ A)(4\ \Omega)\\18\ V \neq 24\ V$

Hence, this does not show Ohm's Law correctly.

CIRCUIT 'C' (BOTTOM-LEFT):

$56\ V=(7\ A)(8\ \Omega)\\56\ V= 56\ V$

Hence, this shows Ohm's Law correctly.

CIRCUIT 'D' (BOTTOM-RIGHT):

$20\ V=(5\ A)(4\ \Omega)\\20\ V= 20\ V$

Hence, this shows Ohm's Law correctly.

Learn more about Ohm's Law here:

https://brainly.com/question/17286882?referrer=searchResults

The attached picture shows Ohm's Law.