Answer:
see the explanation
Step-by-step explanation:
we know that
The circumference of a circle is equal to
[tex]C=\pi D[/tex]
where
D is the diameter
In this problem we have
[tex]C=2.88\ in[/tex]
[tex]\pi=3[/tex]
substitute and solve for D
[tex]2.88=(3)D[/tex]
[tex]D=2.88/3[/tex]
[tex]D=0.96\ in[/tex]
we know that
The length of the row of quarters is equal to multiply the diameter of the quarter by the number of quarters in the row
so
For 4 quarters in the row, the length is equal to --> [tex]0.96(3)=3.84\ in[/tex]
For 6 quarters in the row, the length is equal to --> [tex]0.96(6)=5.76\ in[/tex]
For 12 quarters in the row, the length is equal to -> [tex]0.96(12)=11.52\ in[/tex]