Question

(12 points) An object's velocity is given as v = 2 + 4t - 6t^2. If this object has an initial position of 3 m, what's the object's velocity when t = 2?

Answer 1

Answer:

Here,

Step-by-step explanation:

Here,

v=2 + 4t - 6t²

a=dv/dt =d(2 + 4t - 6t²) /dt

= 4-12t

We have, s=3m and t=2 so,

v=2+4×2-6×2²=-12

a=4-12×2=-20

u=?

Now,

v²=u²+2as

(-12)²=u²+2×(-20)×3

144=u²-120

144-120=u²

24=u²

u=4.89