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Two pots are identical except that the flat bottom of one is aluminum, whereas that of the other is copper. Water in these pots is boiling away at 100.0 ˚C at the same rate. The temperature of the heating element on which the aluminum bottom is sitting is 161 ˚C. Assume that heat enters the water only through the bottoms of the pots and find the temperature of the heating element on which the copper bottom rests.

Respuesta :

Answer:

Explanation:

Rate of flow of heat = K X ( t₂ -t₁ ) xA/L

K is thermal conductivity , t₂ -t₁ = temperature difference , A is area of surface and L is thickness of separating medium

In the given case only K and t₂ are different , otherwise all others are equal.

So

Since rate of heat flow are equal

K₁ X ( t-100) = K₂ X ( 161 - 100 )

t is temperature of source of heat near copper bottom.

K₁ and K₂ are thermal conductivity of copper and aluminium.

K₁ / K₂ = 61/( t - 100)

385/205 = 61/t -100

385t -38500 = 12505

385t = 51005

t = 133.77 C.

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