Answer:
Explanation:
Rate of flow of heat = K X ( t₂ -t₁ ) xA/L
K is thermal conductivity , t₂ -t₁ = temperature difference , A is area of surface and L is thickness of separating medium
In the given case only K and t₂ are different , otherwise all others are equal.
So
Since rate of heat flow are equal
K₁ X ( t-100) = K₂ X ( 161 - 100 )
t is temperature of source of heat near copper bottom.
K₁ and K₂ are thermal conductivity of copper and aluminium.
K₁ / K₂ = 61/( t - 100)
385/205 = 61/t -100
385t -38500 = 12505
385t = 51005
t = 133.77 C.