Answer:
Process S gives a higher net present value
1,237.46 againnst 1,179.46 of process L
It will add a value of 1,237.46
Explanation:
We will calcualte each process present value at the given rate
Process S
The project will last 4 year so the machine will be purchased 2 times
one at the beginning and another at the beginning of the third yar
cash flow 5,000 for 4 year at 10%
[tex]C \times \frac{1-(1+r)^{-time} }{rate} = PV\\[/tex]
C 5000
time 4
rate 0.1
[tex]5000 \times \frac{1-(1+0.1)^{-4} }{0.1} = PV\\[/tex]
PV $15,849.33
Now the present value fo the second machine purchased
[tex]\frac{Maturity}{(1 + rate)^{time} } = PV[/tex]
Maturity (8,000.00)
time 2.00
rate 0.10
[tex]\frac{-8000}{(1 + 0.1)^{2} } = PV[/tex]
PV (6,611.57)
NPV = 15,849.33 - 8,000 - 6,611.57 = 1,237.36
Now the next, process L
This time we don't need to purchase a new machine.
[tex]C \times \frac{1-(1+r)^{-time} }{rate} = PV\\[/tex]
C 4000
time 4
rate 0.1
[tex]4000 \times \frac{1-(1+0.1)^{-4} }{0.1} = PV\\[/tex]
PV $12,679.46
NPV 12,679.46 - 11,500 = 1,179.46