Answer:
Parallelogram
Step-by-step explanation:
We are given that a quadrilateral ABCD with vertices A(-1,0),B(1,2),C(4,2) and D (2,0).
Distance formula :[tex]\sqrt{9x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Using distance formula
AB=[tex]\sqrt{(1+1)^2+(2-0)^2}=\sqrt{4+4}=2\sqrt2[/tex]
BC=[tex]\sqrt{(4-1)^2+(2-2)^2}=3[/tex]
CD=[tex]\sqrt{(2-4)^2+(0-2)^2}=2\sqrt2[/tex]
AD=[tex]\sqrt{(2+1)^2+(0-0)^2}=3[/tex]
AB=CD and BC=AD
From figure ,
The quadrilateral is parallelogram because opposite sides are equal and parallel.
