Respuesta :
Answer:
[tex]\overline{G}= \{1, 2, 3, 4, 5...11, 13, 14...17\}[/tex]
Step-by-step explanation:
[tex]U = \{x|x \in Z^+,x<18 \}[/tex]
[tex]G = \{12x|x \in Z^+ \}[/tex]
[tex]\overline{G}= \{1, 2, 3, 4, 5...11, 13, 14...17\}[/tex]
Answer: The required complement of set G is {5, 7 , 8, 9, 10, 11, 13, 14, 15, 16, 17}.
Step-by-step explanation: Given that U is the set of positive integers less than 18. G is the set of positive factors of 12.
We are to find the complement of set G is universal set U.
According to the given information, we have
U = {1, 2, 3, . . 17}
and
G = {1, 2, 3, 4, 6, 12}.
Therefore, the complement of set G in set U is given by
[tex]G^\prime=U-G=\{5,7,8,9,10,11,13,14,15,16,17,18\}.[/tex]
Thus, the required complement of set G is {5, 7 , 8, 9, 10, 11, 13, 14, 15, 16, 17}.