Basic points to remember
1) perpendicular drawn from centre always bisects chord
2) diameter is double of radius
Now get revert back to Question
18= chord length
So, chord/2 = 18/2 = 9
26 = diameter
26/2 = 13= radius
Now As it forms right angled triangle
Hence
x= √( 13^2 - 9^2)
= √169-81
= √88
= 2√22
Answer:
x ≈ 9.4
Step-by-step explanation:
The segment from the centre is a perpendicular bisector of the chord.
Using Pythagoras' identity in the right triangle formed with hypotenuse 13 and legs 9 and x
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
x² + 9² = 13²
x² + 81 = 169 ( subtract 81 from both sides )
x² = 88 ( take the square root of both sides )
x = [tex]\sqrt{88}[/tex] = 2[tex]\sqrt{22}[/tex] ≈ 9.4 ( to 1 dec. place )
