Respuesta :

zumar

Step-by-step explanation:

As equilateral triangle have equal sides

By applying Pathagores theorem

[tex](hyp)^2=(per)^2+(base)^2[/tex]

by putting values

[tex](a)^2=(per)^2+( \frac{a}{2} )^2[/tex]

[tex]a^2- \frac{a^2}{4} =(per)^2[/tex]

by taking lcm on L:H:S

[tex] \frac{4a^2-a^2}{4} =(per)^2[/tex]

[tex] \frac{3a^2}{4} = (per)^2[/tex]

by taking square root on both side

[tex] \frac{ \sqrt{3}a }{2} =(per)[/tex]

i hope u will understand