Answer:
1.94 kg
Explanation:
we have given density of water = 1 gm/[tex]cm^3[/tex]
the initial reading of the scale = 19 N
change in reading of scale =10 N
we have to find the mass of the block when the block is lowered in water
mass of the block when it is lowered in the water is given by
[tex]w_b=\frac{f}{g}[/tex]
here g is the gravity of acceleration which value is given by 9.8 [tex]m/sec^2[/tex]
so the mass of the block =[tex]\frac{19}{9.8}=1.94\ kg[/tex]