Answer:
a) a = 3.29 m/s²
b) a = 3.51 m/s²
Explanation:
mass of dogs = 19 kg
loaded sled mass = 210 Kg
a)writing all the forces in x direction
[tex]\sum F_x=8F_d-f_{s(max)}= (m_s+8m_d)a\\a=\dfrac{8F_d-\mu_sm_sg}{m_s+8m_d}\\a=\dfrac{8\times 185-(0.14)(210)(9.81)}{210+8(19)}[/tex]
a = 3.29 m/s²
b) acceleration when sled start to move the friction will now be acting will be kinetic friction.
[tex]a=\dfrac{8F_d-\mu_sm_sg}{m_s+8m_d}\\a=\dfrac{8\times 185-(0.1)(210)(9.81)}{210+8(19)}[/tex]
a = 3.51 m/s²