Answer:
tetraaquadichlorochromium(III) chloride
Explanation:
Given,
The complex : [Cr(H₂O)₄Cl₂]Cl
The oxidation number of Chromium is:
x +0 +2(-1) = +1
x = +3
The complex contains ligands H₂O and chloride ion.
Cl⁻ is written as chloro and H₂O as aqua. H₂O is written first because aqua will come before chloro in the English alphabet.
4 molecules of H₂O are acting as ligands in the complex. So, written as: tetraaqua
2 molecules of Cl⁻ are acting as ligands in the complex. So, written as: dichloro
One chloride ion acts as a spectator anion.
The name of the complex is:
tetraaquadichlorochromium (III) chloride
