Question

​Claim: Most adults would erase all of their personal information online if they could. A software firm survey of 528 randomly selected adults showed that 62​% of them would erase all of their personal information online if they could. Find the value of the test statistic.

Answer 1

Answer:

5.514

Step-by-step explanation:

we have given $\bar{p}$=62% =0.62

n=528

claim : most of adults erase all their personal information online ($p> 0.5$

p=0.5 q=1-p=1-0.5=0.5

now test statistic is

$\frac{\bar{p}-p}{\sqrt{\frac{pq}{n}}}=\frac{0.62-0.5}{\sqrt{\frac{0.5\times 0.5}{528}}}=5.514$

so the test  statistic =5.514

Answer 2

The test statics is $5.514$

we have given $\bar{p}$=$62$ % =$0.62$  and $n=528$

Claim : Most of adults erase all their personal information online $\therefore p>2$

Hence, at $p=0.5, q=1-p=1-0.5=0.5$

Therefore test statistic is

$\frac{\bar{p}-q}{\sqrt{\frac{\bar{p}q}{n}}}=\frac{{0.62}-0.5}{\sqrt{\frac{{0.62}\times 0.5}{528}}}=5.514$

So the test  statistic =$5.514$

Learn more about test statics.

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