Answer:
a) 0.23235
b) 0.53806
c) 0.22959
Step-by-step explanation:
Given-
Adults having cashews as their favorite kind of nut [tex]= 0.31[/tex]
Adults not having cashews as their favorite kind of nut [tex]= 1-0.31\\= 0.69[/tex]
a) Exactly three
[tex]\frac{12}{3} * (0.31)^3* (0.69)^9\\= 0.23235[/tex]
Thus, the probability that three adults have cashews as are their favorite nut is 0.23235
b) at least four
[tex]1-P(1)-P(2)-P(3)\\[/tex]
[tex]1-[({\frac{12}{1} * (0.31)^1* (0.69)^{11})+({\frac{12}{2} * (0.31)^2* (0.69)^{10})+({\frac{12}{3} * (0.31)^3* (0.69)^{9})][/tex]
[tex]=0.53806[/tex]
c) at most two
[tex]({\frac{12}{1} * (0.31)^1* (0.69)^{11})+({\frac{12}{2} * (0.31)^2* (0.69)^{10})\\= 0.22959[/tex]