Answer:
[tex]f_b = 29.98 Hz[/tex]
Explanation:
speed of bat = 6 m/s
sound wave frequency emitted by bat = 30.0 kHz
as we know,
speed of sound (c)= 343 m/s
[tex]f_w = f(\dfrac{c+v_r}{c+v_s})[/tex]
[tex]f_w = 30(\dfrac{343+0}{343+6})[/tex]
[tex]f_w = 29.48 Hz[/tex]
now frequency received by bat is equal to
[tex]f_b = f(\dfrac{c+v_r}{c+v_s})[/tex]
[tex]f_b = 29.48(\dfrac{343+6}{343+0})[/tex]
[tex]f_b = 29.98 Hz[/tex]
hence the frequency hear by bat will be 29.98 Hz