Question

A chess player won 25 percent of the first 20 games he played and all of his remaining games. What is the ratio of the number of games he won to the number of the games he lost? (Assume there cannot be a draw in the game.)

Answer 1

Answer: 1:3

Step-by-step explanation:

Given : The number of games played by the player = 20

Winning percentage = 25% =0.25

Then , the number of games he won = $0.25\times20=5$

We assume that there cannot be a draw in the game.

Then , the number of games he had lost = $20-5=15$

Now, the  ratio of the number of games he won to the number of the games he lost is given by :-

$\dfrac{5}{15}=\dfrac{1}{3}=1:3$

Hence, the ratio of the number of games he won to the number of the games he lost = 1:3