Question

What are the exact solutions of x2 − 3x − 5 = 0? x = the quantity of negative 3 plus or minus the square root of 29 all over 2 x = the quantity of 3 plus or minus the square root of 29 all over 2 x = the quantity of 3 plus or minus the square root of 11 all over 2 x = the quantity of negative 3 plus or minus the square root of 11 all over 2

Answer 1

Given $x^2-3x-5=0$ we cannot factor therefore we are forced to use quadratic equation to get solutions: $x_1=\frac{3-\sqrt{29}}{2},x_2=\frac{3+\sqrt{29}}{2}$

Hope this helps.

r3t40

Answer 2

Answer:

The correct option is 2.

Step-by-step explanation:

The given equation is

$x^2-3x-5=0$

If a quadratic equation is defined as $ax^2+bx+c=0$, then accoding to the quadratic formula

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

In the given equation $a=1, b=-3,c=-5$.

Using quadratic formula we get,

$x=\frac{-(-3)\pm \sqrt{(-3)^2-4(1)(-5)}}{2(1)}$

$x=\frac{3\pm \sqrt{9+20}}{2}$

$x=\frac{3\pm \sqrt{29}}{2}$

The exact solutions of the given equations are $x=\frac{3\pm \sqrt{29}}{2}$.

Therefore the correct option is 2.