Answer:
33 gm.
Explanation:
Heat required by coffee in evaporation = m L = m x 560 cals
Heat released by coffee in cooling = m c Δ T = 350 X 1 X 50 = 17500 cals
Heat released by glass cup = 100 x .2 x 50 = 1000 cals ( specific heat of glass is .2 cals per gram per k)
Total heat released = 18500 cals
Heat gained = heat lost
m x 560 = 18500
m = 33 gm.