Respuesta :
Answer:
a) B = 3 × 10⁻⁵ T
b) The earth's magnetic field is around 5 × 10⁻⁵ T. thus, the obtained magnetic field is consistent with the earth's magnetic field
Explanation:
Given:
Speed of proton, v = 5.00 × 10⁷ m/s
Magnetic force, F = 1.70×10⁻¹⁶ N
Angle between the force and the velocity, Θ = 45°
a) Now,
the magnetic force is given as:
F = qvBsinΘ
where,
q is the charge = 1.6 × 10⁻¹⁹ C for proton
B is the Magnetic field
on substituting the values in the above equation, we get
1.70×10⁻¹⁶ N = 1.6 × 10⁻¹⁹ 5.00 × 10⁷ × B × sin45°
or
B = 3 × 10⁻⁵ T
b) The earth's magnetic field is around 5 × 10⁻⁵ T. thus, the obtained magnetic field is consistent with the earth's magnetic field
a) The strength of the magnetic field is B = 3 × 10⁻⁵ T
b) The earth's magnetic field is around 5 × 10⁻⁵ T. thus, the obtained magnetic field should be consistent with the earth's magnetic field
Magnetic force:
a.
Since
Speed of proton, v = 5.00 × 10⁷ m/s
Magnetic force, F = 1.70×10⁻¹⁶ N
The angle between the force and the velocity, Θ = 45°
The magnetic force should be
F = qvBsinΘ
here
q is the charge = 1.6 × 10⁻¹⁹ C for proton
B is the Magnetic field
So,
= 1.70×10⁻¹⁶ N = 1.6 × 10⁻¹⁹ 5.00 × 10⁷ × B × sin45°
or
B = 3 × 10⁻⁵ T
b) The earth's magnetic field is around 5 × 10⁻⁵ T. due to this, the obtained magnetic field should be consistent with the earth's magnetic field
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