Question

Imagine that a hypothetical life form is discovered on our moon and transported to Earth. On a hot day, this life form begins to sweat, and it is determined that the heat of vaporization of its sweat is 241 cal/g. The scientist observing the extraterrestrial life form also begins to sweat. The heat of vaporization of the scientist's sweat is 580 cal/g at the skin's surface. If both the extraterrestrial life form and the scientist lose 186 g of sweat over the course of one hour, calculate the heat lost by each body from the vaporization of sweat.

Answer 1

Answer:

131.4 g by strange creature and  54.6 g by scientist

Explanation:

Since the temperature difference between the surroundings and body of both the living beings (average temperature) are the same , amount of heat radiated must have been the same in one hour.

So if we consider X amount of sweat of hypothetical life is vaporized , then amount of sweat for scientist will be (186-X)g.

heat lost by extra-terrestrial life = X x 241 cals

heat lost by scientist = ( 186 - X) x 580 cals

So 241X = ( 186 - X) x580

241X + 580 X = 186 x 580 = 107880

821 X = 107880

X = 131.4 g and 186- 131.4 = 54.6 g .

Answer 2

Answer:

Total heat lost = 153450cal

Explanation:

Assumptions:

1. both the hypothetical life form and the scientist lose 186g of sweat per hour each
2. all heat lost is due to vaporization of sweat

Heat Lost by Hypothetical Life Form

$Q=m*l$

$Q=186g*241cal/g$

$Q=44826cal$

Heat Lost by Scientist

$Q=m*l$

$Q=186g*580cal/g$

$Q=107880cal$

Total heat lost = 44826cal + 107880cal

Total heat lost = 153450cal