Answer:
0.0392 m³
Explanation:
Given:
Density of the styrofoam, ρ' = 32 kg/m³
Now, let the volume of the slab = V
the submerged volume be = V ;
now, the volume of water displaced will be V
thus,
the buoyant force acting will be = ρVg
where,
ρ is the density of water
g is the acceleration due to gravity
now, the
total downward force acting = weight of the boy + weight of the slab
total downward force acting =38 × g + ρ' × V × g
for the no sinking condition,
bouyant force should be equal to the total downward force
thus,
ρ × V × g = 38 × g + ρ' × V × g
or
ρ × V = 38 + ρ' × V
on subtituting the values
V ( 1000 - 32 ) = 38 ;
or
V = 0.0392 m³