Answer: There are 70 houses that have exactly two of these amenities.
Step-by-step explanation:
Number of house in a certain development = 150
Number of houses have air conditioning n(A)= [tex]0.6\times 150=90[/tex]
Number of houses have sunporch n(B) = [tex]0.5\times 150=75[/tex]
Number of houses have swimming pool n(C) = [tex]0.3\times 150=45[/tex]
Number of houses have all three amenities = 5
Number of houses have none of them = 5
So, remaining houses = 150-5=145
As we know the rule of sets:
[tex]n(A\cup B\cup C)=n(A)+n(B)+n(C)-n(A\cap B)-n(B\cap C)-n(C\cap A)+n(A\cap B\cap C)\\\\145=90+75+45-n(A\cap B)-n(B\cap C)-n(C\cap A)+5\\\\145=215-n(A\cap B)-n(B\cap C)-n(C\cap A)\\\\145-215=-n(A\cap B)-n(B\cap C)-n(C\cap A)\\\\-70=-n(A\cap B)-n(B\cap C)-n(C\cap A)\\\\n(A\cap B)+n(B\cap C)+n(C\cap A)=70[/tex]
Hence, there are 70 houses that have exactly two of these amenities.