Question

The buoyant force that is exerted by a fluid on an object that displaced a volume Vdisp is written as: Fbfo=ρfVdispg. A block of wood with a mass of 750.0 g is placed in a container of water. What volume of water must this block displace in order for it to float on the water surface?

Answer 1

Answer:

750 cm^3

Explanation:

mass of wood = 750 g

Buoyant force acting on the wood = Volume x density of wood x gravity

According to the Archimedes Principle, the buoyant force acting on the wood is equal to the weight of water displaced by the wood

So, the weight of water = 750 g

Volume of water = mas of water / density of water = 750 / 1 = 750 cm^3