Respuesta :
Answer:
segment AB ≅ segment BC because their arcs are congruent; therefore, ΔABC is an isosceles triangle ⇒ answer D
Step-by-step explanation:
* Lets revise some facts in the circle
- If a circle is circumscribed around a triangle, then the vertices of the
triangle divide the circle into three arcs
- The three sides of the triangle are the chords of the circle
- Each chord in the circle subtended by an arc
- If two arcs equal, then they are subtended equal chords
* Lets solve the problem
∵ Circumscribed circle D around triangle ABC
- The vertices of triangle ABC lie on the circumference of the circle
∴ AB , BC , AC are the chords of the circle
- Arcs AB and AC are congruent
∵ Arc AB ≅ arc AC
∵ Arc AB subtended the chord AB
∵ Arc AC subtended the chord AC
∴ AB = AC
∵ AB = 6 inches
∴ AC = 6 inches
- The triangle with two equal sides is called an isosceles triangle
∴ Δ ABC is an isosceles triangle
∴ Noah know that the top layer of his cake is an isosceles triangle
* segment AB ≅ segment BC because their arcs are congruent;
therefore, ΔABC is an isosceles triangle.
The legs of an isosceles triangle are equal, therefore, ΔABC is an
isosceles triangle.
The statement that gives what Noah knows is option D.
- D. Segment [tex]\overline{AB}[/tex] ≅ segment [tex]\overline{BC}[/tex] because their arcs are congruent; therefore, ΔABC is an isosceles triangle
Reasons why the above option is correct
The given information are;
Number of layers in the cake = 2
Shape of the top layer of the cake = Triangle
Shape of the bottom layer of the cake = Circle
Length of segment [tex]\overline{AB}[/tex] = 6 inches
[tex]\widehat{AB}[/tex] ≅ [tex]\widehat{AC}[/tex]
The center of the circumscribed circle = Point D
Required:
What Noah knows about the top layer (the triangle ΔABC)
Solution:
According to equal chords in equal circle theorem, we have that if two
arcs are equal, the chords by which they are subtended are also equal.
Therefore;
The chord that subtend arc [tex]\widehat{AB}[/tex], which is segment [tex]\overline{AB}[/tex] is equal to the chord that subtends arc [tex]\mathbf{\widehat{AC}}[/tex] which is chord [tex]\overline{AC}[/tex]
[tex]\overline{AB}[/tex] = [tex]\overline{AC}[/tex], therefore, [tex]\overline{AB}[/tex] ≅ [tex]\overline{AC}[/tex], and ΔABC is an isosceles triangle
What is known from the given information is therefore;
- Segment [tex]\underline{\overline{AB} \cong \overline{AC}}[/tex] because their arcs are congruent; therefore, ΔABC is an isosceles triangle.
Learn more about isosceles triangles here:
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