Question

Which values for h and k are used to write the function f(x)=x^2+12x+6 in vertex form?

A. h=6, k=36
B. h=−6, k=−36
C. h=6, k=30
D h=−6, k=−30

Answer 1

Answer:

D h=−6, k=−30

Step-by-step explanation:

we know that

The equation of a vertical parabola in vertex form is equal to

$f(x)=a(x-h)^{2}+k$

where

a is a coefficient

(h,k) is the vertex

we have

$f)x)=x^{2} +12x+6$

Convert to vertex form

Complete the square

$f)x)-6=x^{2} +12x$

$f)x)-6+36=(x^{2} +12x+36)$

$f)x)+30=(x^{2} +12x+36)$

$f)x)+30=(x+6)^{2}$

$f)x)=(x+6)^{2}-30$ -----> equation in vertex form

therefore

The vertex is the point (-6,-30)

h=-6, k=-30

Answer 2

Answer:

the answer is D. h=−6, k=−30

Step-by-step explanation:

I got it right thanks to the person who answered first