Respuesta :
Answer:
d) 12
Step-by-step explanation:
Given:
Right triangle with side 9+7=16
let the third side of bigger triangle be y
and perpendicular line between 9 and 7 be z
Now:
By Pythagoras theorem:
(16)^2=x^2+y^2
x^2=256-y^2
Also
y^2=z^2 +7^2
z^2=y^2-49
and
x^2=9^2 + z^2
Now substituting z^2=y^2-49 in above we get:
x^2=81 + y^2-49
x^2=32+y^2
Adding x^2=256-y^2 and x^2=32+y^2 we get:
2x^2= 288
x^2=144
x=12 !
Answer:
The value of x is 12
Step-by-step explanation:
Let ABC is a triangle in which,
AB = x, BD = 9 unit, DC = 7 unit,
Where, D ∈ BC,
∵ ∠ABC ≅ ∠DBC ( common angles )
Also, ∠BAC ≅ ∠ADB ( right angles )
By AA similarity postulate,
[tex]\triangle ABC\sim \triangle DBA[/tex]
∵ Corresponding sides of similar triangles are in same proportion,
[tex]\implies \frac{AB}{BC}=\frac{DB}{AB}[/tex]
[tex]\implies \frac{x}{9+7}=\frac{9}{x}[/tex] ( ∵ BC = BC + DC )
[tex]x^2 = 144[/tex]
[tex]\implies x = 12[/tex] ( Sides can not be negative )
Hence, the value of x is 12.