Question

16 individuals in a population of 100 are homozygous recessive for a particular trait (A or a). What percent of the alleles in that population are dominant?

Answer 1

Answer:

36 individuals

Explanation:

In a 100 persons population, 16 represent the 16% of the total or 0.16 This is the percent of recessive alleles.

You know the formulas $p^{2} +2pq+q^{2} =1$ and $p+q=1$

Where $q^{2}$ is the percent of recessive alleles and $p^{2}$ is the percent of dominant alleles.

If $q^{2} =0.16$ then $q=\sqrt{0.16}=0.4$

and because $p+q=1$, $p+0.4=1$ then $p=0.6$ and $p^{2}=0.36$

The percent of dominant alleles in this population is 0.36 or 36%, wich means 36 individuals.