Question

How many moles of HCl are present in 1.2 L of a 1.84 M HCl solution?

Select one:
a. 17
b. 1.7e4
c. 20
d. 620

Answer 1

Answer:

2.21 moles of HCl are present in 1.2 L of a 1.84 M HCl solution

Explanation:

Molarity (M),

Molality (m),

Normality (N),

Mass %,

Parts per million(ppm), billion(ppb), thousands(ppt) are some of the terms we use to represent the concentration of the solution that is to represent the amount of solute present in a solvent.

Molarity is moles of solute present in 1L of the solution.

The formula to find Molarity is  

$Molarity  = \frac {(moles solute)}{(volume of solution in L) }$ and its unit is mol/L

Rearranging the formula

We get                        

moles  = Molarity × Volume

Plugging in the values  

$moles=1.84M \times 1.2L (M=mol/L)$

$=1.84 mol/L\times1.2L=2.21 moles$ (Answer)