Respuesta :
Answer:
see explanation
Step-by-step explanation:
(i)
Multiply each of the elements in P by 4
4 [tex]\left[\begin{array}{ccc}0&-1\\1&0\\\end{array}\right][/tex]
= [tex]\left[\begin{array}{ccc}0&-4\\4&0\\\end{array}\right][/tex]
(ii)
Subtract the corresponding elements in Q from P
[tex]\left[\begin{array}{ccc}0&-1\\1&0\\\end{array}\right][/tex] - [tex]\left[\begin{array}{ccc}1&-2\\0&1\\\end{array}\right][/tex]
= [tex]\left[\begin{array}{ccc}0-1&-1-(-2)\\1-0&0-1\\\end{array}\right][/tex]
= [tex]\left[\begin{array}{ccc}-1&3\\1&-1\\\end{array}\right][/tex]
(iii)
Multiply and sum corresponding elements in row 1/column 1, row 1/ column 2, row 2/column 1, row 2/ column 2
[tex]\left[\begin{array}{ccc}0&1\\1&0\\\end{array}\right]\left[\begin{array}{ccc}0&1\\1&0\\\end{array}\right][/tex]
= [tex]\left[\begin{array}{ccc}(0(0)+(1(1)&0(1)+1(0)\\1(0)+0(1)&1(1)+0(0)\\\end{array}\right][/tex]
= [tex]\left[\begin{array}{ccc}0+1&0+0\\0+0&1+0\\\end{array}\right][/tex]
= [tex]\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right][/tex]
(iv)
Multiply and sum corresponding elements in row 1/ column 1, row 2/ column 1
[tex]\left[\begin{array}{ccc}1&-2\\0&1\\\end{array}\right][/tex] [tex]\left[\begin{array}{ccc}-3\\5\\\end{array}\right][/tex]
= [tex]\left[\begin{array}{ccc}1(-3)+(-2)5\\0(-3)+1(5)\\\end{array}\right][/tex]
= [tex]\left[\begin{array}{ccc}-3-10\\0+5\\\end{array}\right][/tex]
= [tex]\left[\begin{array}{ccc}-13\\5\\\end{array}\right][/tex]