Answer:
a)[tex]\dot V = 0.28335 m3/s[/tex]
b)[tex]\dot W_{in} = 259.63 kW[/tex]
Explanation:
part a)
inlet volume of air V1 is given as [tex]= \frac{RT_1}{P_1}[/tex]
putting all value in the above formula
[tex]V_1 = = \frac{0.1889 kpa - m3/kg .K * 300 K}{100kPa}[/tex]
[tex]V_1 = 0.5667 m3/kg[/tex]
we know that volume of flow rate
[tex]\dot V = \dot mV_1[/tex]
[tex]\dot V = 0.5 kg/s *0.5667 m3/kg = 0.28335 m3/s[/tex]
[tex]\dot V = 0.28335 m3/s[/tex]
part b
we know that total energy remain constant, so we have
E_in - E_out = Change in energy in system
E_in = E_out
therefore
[tex]\dot W_{in} + \dot m h_1 =\dot m h_2[/tex]
[tex]\dot W_{in} = \dot m h_2- \dot m h_1[/tex]
the power input to the compressor is
[tex]\dot W_{in} = \dot m c_p (h_2- h_1 )[/tex]
[tex]\dot W_{in} = 0.5*5.1926*(450-350 )[/tex]
[tex]\dot W_{in} = 259.63 kW[/tex]