Question

Chose the equation that represents the line that passes through the point (2,6) and has a slope of -5

Answer 1

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

(x₁, y₁) - point on a line

We have the slope m = -5, and the point (2, 6).

Substitute:

$y-6=-5(x-2)$

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept

Convert:

$y-6=-5(x-2)$           use the distributive property a(b + c) = ab + ac

$y-6=-5x+(-5)(-2)$

$y-6=-5x+10$            add 6 to both sides

$y=-5x+16$

The standard form of an equation of a line:

$Ax+By=C$

Convert:

$y=-5x+16$            add 5x to both sides

$5x+y=16$