Answer: (71.36, 78.64)
Step-by-step explanation:
Given : Sample size : n= 50
Sample mean : [tex]\overlien{x}=75\text{ lb}[/tex]
Variance : [tex]\sigma^2=100\text{ lb}[/tex]
Standard deviation : [tex]\sigma=10\text{ lb}[/tex]
Significance level : [tex]1-0.99=0.01[/tex]
Critical value : [tex]z_{\alpha/2}=\pm2.576[/tex]
The confidence interval for population mean is given by :-
[tex]\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}[/tex]
[tex]=75\pm(2.576)\times\dfrac{10}{\sqrt{50}}\\\\\approx75\pm3.64\\\\=(71.36,\ 78.64)[/tex]
Hence, the 99% confidence interval for population mean [tex]\mu[/tex] = (71.36, 78.64)