A charge q = 2.00 μC is placed at the origin in a region where there is already a uniform electric field = (100 N/C) î. Calculate the flux of the net electric field through a Gaussian sphere of radius R = 10.0 cm centered at the origin. (ε0 = 8.85 × 10-12 C2/N ∙ m2)

Respuesta :

Answer:

[tex]\phi = 2.26 \times 10^5 Nm^2/C[/tex]

Explanation:

Due to uniform electric field net flux through a closed surface is always zero

so here we have to find the net flux through a sphere due to a point charge placed at origin and due to a uniform electric field

so here we will have

[tex]\phi = \frac{q}{\epsilon_o}[/tex]

now we have

[tex]\phi = \frac{2 \times 10^{-6}}{8.85 \times 10^{-12}}[/tex]

[tex]\phi = 2.26 \times 10^5 Nm^2/C[/tex]

Due to external uniform field the electric flux is zero

so the total flux is only due to charge and it is equal to

[tex]\phi = 2.26 \times 10^5 Nm^2/C[/tex]

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