Solve 6x + 2 = 10 for x using the change of base formula log base b of y equals log y over log b.

Answer:
x= -0.715
Step-by-step explanation:
6^x+2 = 10
Step 1: Apply ln rule on both sides
ln rule: x^y = z
ln rule: (y)ln(x) = ln(z)
6^x+2 = 10
(x+2)*ln(6) = ln(10)
(x+2) = ln(10)/ln(6)
x+2 = 1.285
x = -0.715
Therefore, the right answer is the second option -0.715
!!
Answer:
The answer is -0.715
Step-by-step explanation:
Firstly, we use the change of base formula. The base must be 6 because the "x" variable is a power of it.
[tex]6^x^+^2=10\\\\log_{6} (6^x^+^2)=log_{6} (10)\\[/tex]
Then, we can use the property logarithm power rule:
[tex]log_{b}(x^y)=y* log_{b}(x)[/tex]
So,
[tex](x+2)*log_{6} (6)=log_{6} (10)\\log_{6} (6)=1\\x+2=log_{6} (10)\\\\log_{6} (10)=\frac{log(10)}{log(6)}\\log(10)=1\\\\x+2=\frac{1}{log(6)} \\x=\frac{1}{log(6)}-2[/tex]
Finally, the value of [tex]\frac{1}{log(6)} =1.285[/tex], therefore:
[tex]x=1.285-2=-0.715[/tex]