Answer:
4.769 L
Explanation:
initial volume [tex]v_1=4.2\ ltr[/tex]
We have to find the final volume [tex]v_2[/tex]
initial temperature [tex]T_1[/tex]=0°C=273+0=273 K
final temperature [tex]T_2[/tex]=37°C=273+37=310 k
At constant pressure according to Charles law
[tex]\frac{V_2}{V_1}=\frac{T_2}{T_1}[/tex]
[tex]V_2=\frac{T_2}{T_1}\times V_1[/tex]
[tex]V_2=\frac{310}{273}\times 4.2=4.769 L[/tex]
So the final volume will be 4.769 L