Question

Will give brainliest need urgent help

Answer 1

Answer: 12

I belive the answer would be 12

Answer 2

For this case we have the following expression:

$(a-1) + \frac {a ^ 2-b ^ 2} {1-ab} + \frac {2 (a-b)} {2b}$

We must find the value of the expression when:

$a = 2\\b = -1$

Substituting the values we have:

$(2-1) + \frac {2 ^ 2 - (- 1) ^ 2} {1-2 (-1)} + \frac {2 (2 - (- 1))} {2 (-1)} =\\1+ \frac {4-1} {1 + 2} + \frac {2 (2 + 1)} {- 2} =\\1+ \frac {3} {3} + \frac {2 (3)} {- 2} =\\1 + 1 + \frac {6} {- 2} =\\1 + 1-3 =\\2-3 =\\-1$

Answer:

-1