Answer:
Surface area = [tex]x^{2} +\frac{16}{x}[/tex] m².
And domain will be x∈ (0,∞)
Step-by-step explanation:
An open rectangular box with volume 4 m³ has a square base.
The length of a side of the base is x
We can say that [tex]x\times x\times h=4[/tex]
=> [tex]x^{2} h=4[/tex]
[tex]h=\frac{4}{x^{2} }[/tex]
Surface area can be found as: [tex]x^{2} +4hx[/tex]
[tex]x^{2} +(4x\times\frac{4}{x^{2}})[/tex]
Surface area = [tex]x^{2} +\frac{16}{x}[/tex] m².
And domain will be x∈ (0,∞) we can also say x>0
x is greater than zero as the surface area will always be a positive value and x cannot be negative.