Respuesta :
Answer:
Step-by-step explanation:
This is a two tailed test for comparison of two variances at 2% significance level
[tex]n_1 = 8: n_2 =6\\s_1 =10: s_2 = 7[/tex]
deg of freedom = 7
F statistic = [tex]\frac{s_1^2}{s_2^2} =\frac{100}{49} \\=2.041[/tex]
p value = 0.4496
1. State the decision rule for 0.02 significance level. (Round your answer to 1 decimal place.) Reject H0 if F >10.4555
2.F=2.041
3. _Accept_________H0. There is __no significant____ in the variations of the two populations
Answer:
Step-by-step explanation:
From the question; for 0.02 level and [tex]n_1 -1 = 7[/tex] ; [tex]n_2 -1 = 5[/tex]; degree of freedom.
The critical value (F) = 0.1340 and 10.4555
Decision rule: reject [tex]H_o[/tex] if test statistic [tex]F>10.5[/tex] ( to one decimal place) or [tex]F<0.1[/tex] ( to on decimal place)
Test statistic:
[tex]F = (\frac{s_1}{s_2})^2 \\ \\ = (\frac{10}{7})^2 \\ \\[/tex]
= 2.0408
= 2.04 (to two decimal place)
As test statistic does not fall into critical region we can not reject null hypothesis.
Conclusion:
Accept [tex]H_o[/tex] .There is significant variations of the two population.
