Question

Determine the sample size n needed to construct a 99​% confidence interval to estimate the population proportion for the following sample proportions when the margin of error equals 6​%.

Answer 1

Answer with explanation:

We have to construct 99% confidence interval when margin of error is equal to 6%.

So, population that is sample size will lie between confidence interval

99%-6% < n  < 99%+6%

93% < n < 105 %

$z_{0.93}< n < z_{1.05}\\\\0.8238<n({\text{Population Proportion})<0.8531}\\\\ \text{Approximately}\\\\82.38 <n({\text{Population Proportion})<85.31$