Question

A daredevil is shot out of a cannon at 45.0° to the horizontal with an initial speed of 25.0 m/s. A net is positioned a horizontal distance of 50.0 m from the cannon. At what height above the cannon should the net be placed in order to catch the daredevil?

Answer 1

Answer:

$10.8$meters

Step-by-step explanation:

The horizontal distance traveled is equal to $50$

velocity in the horizontal direction $= 25* cos(45)\frac{m}{s}$

Time taken to travel is horizontal distance

$= \frac{50}{25*cos(45)}\\ = 2.83$seconds

The vertical height is given by

$Y = v_i*t+ \frac{1}{2} a*t^2$

where

$v_i=$initial velocity

$a=$acceleration due to gravity

Substituting the given values in above equation, we get -

$Y = (25 * sin(45))* 2.83+\frac{1}{2} * 9.8* 2.83*2\\Y = 10.8$meter