Answer:
Pool will be filled in 280 hours
Step-by-step explanation:
Inlet pipe fills in 40 hours = 1 pool
Inlet pipe fills in 1 hours = [tex]\frac{1}{40}[/tex]
Drain pipe empty in 42 hours = 1 pool
Drain pipe empty in 1 hour = [tex]\frac{1}{42}[/tex]
If both pipes are opened together
then in pool fills in 1 hour = [tex]\frac{1}{40}[/tex] - [tex]\frac{1}{42}[/tex]
on simplifying the right side ,we get [tex]\frac{42-40}{(40)(42)}[/tex]
= [tex]\frac{2}{(40)(42)}[/tex]
= [tex]\frac{1}{840}[/tex]
[tex]\frac{1}{840}[/tex] pool fills in 1 hour
1 pool will be filled in 840 hours
[tex]\frac{2}{3}[/tex] pool is filled
empty pool = 1 - [tex]\frac{2}{3}[/tex] = [tex]\frac{1}{3}[/tex]
therfore [tex]\frac{1}{3}[/tex] pool will be filled in [tex]\frac{1}{3}[/tex]X 840 =
= 280 hours