Answer: C. 82.26%
Explanation:
Given : The red blood cell counts of women are normally distributed with
[tex]\mu=4.577\text{ million cells per microliter}[/tex]
[tex]\sigma=0.382\text{ million cells per microliter}[/tex]
Let X be the random variable that represents the red blood cell counts of randomly selected woman.
Z-score : [tex]z=\dfrac{X-\mu}{\sigma}[/tex]
For X=4.2
[tex]z=\dfrac{4.2-4.577}{0.382}\approx-0.99[/tex]
For X=5.4
[tex]z=\dfrac{5.4-4.577}{0.382}\approx2.1544[/tex]
Now, the probability that the women have red blood cell counts in the normal range from 4.2 to 5.4 million cells per microliter will be :-
[tex]P(4.2<X<5.4)=P(-0.99<z<2.15)\\\\=P(z<2.1544)-P(z<-0.99)\\\\=0.9843955-0.1618458=0.8225497\approx0.8226=82.26\%[/tex]
Hence, 82.26% of women have red blood cell counts in the normal range from 4.2 to 5.4 million cells per microliter.