Answer:
2.10 g
Explanation:
Write the unbalanced reaction:
Fe + O₂ → Fe₂O₃
Balance it:
4Fe + 3O₂ → 2Fe₂O₃
Now use stoichiometry. Convert mass of Fe to moles of Fe:
1.47 g Fe × (1 mol Fe / 55.8 g Fe) = 0.0263 mol Fe
Convert moles of Fe to moles of Fe₂O₃:
0.0263 mol Fe × (2 mol Fe₂O₃ / 4 mol Fe) = 0.0132 mol Fe₂O₃
Finally, convert moles of Fe₂O₃ to mass of Fe₂O₃:
0.0132 mol Fe₂O₃ × (159.7 g Fe₂O₃ / mol Fe₂O₃) = 2.10 g Fe₂O₃
