Explanation:
It is given that,
Velocity of particle 1, u₁ = 10 m/s
Velocity of particle 2, u₂ = 5 m/s
Let v₁ and v₂ are the final speed of both particles after the collision. Applying the conservation of momentum as :
[tex]mu_1+mu_2=mv_1+mv_2[/tex]
[tex]15=v_1+v_2[/tex]......................(1)
For an elastic collision, the coefficient of restitution is equal to 1 as :
[tex]\dfrac{v_2-v_1}{u_1-u_2}=1[/tex]
[tex]\dfrac{v_2-v_1}{5}=1[/tex]
[tex]{v_2-v_1}=5[/tex]................(2)
On solving equation (1) and (2), we get,
[tex]v_1=5\ m/s[/tex]
[tex]v_2=10\ m/s[/tex]
So, the speeds of particle 1 and particle 2 after the collision is 5 m/s and 10 m/s respectively. Hence, this is the required solution.