Question

what are the real number solutions for x^2-3x+8=0

Answer 1

Answer:

There is no real solutions

Step-by-step explanation:

We have to count delta:

∆=(-3)²-4*8*1=-23.

Because ∆ is less than zero, your equation has only 2 imaginary solutions.

This equation hasn't got any real solutions (because √∆ isn't real)

Answer 2

Answer:

There are 0 real number solutions.

Step-by-step explanation:

You can use the discriminant to find the number of real number solutions.

The discriminant equation is:

${b}^{2} - 4ac$.

a=1

b=-3

c=8

If the discriminant is positive, there are 2 real number solutions. If the discriminant is negative, there are 0 real number solutions. If the discriminant is 0, there is 1 real number solution.

${( - 3)}^{2} - 4(1)(8)$

= 9 - 32

= -23

The discriminant is negative.

0 real number solutions.