Answer:
1) [tex]\frac{7}{20}[/tex]
2) [tex]1\frac{1}{12}[/tex]
3) [tex]\frac{7}{8}[/tex]
Step-by-step explanation:
1) Given problem,
[tex]\frac{3}{5}-\frac{1}{4}[/tex]
LCM(5,4) = 20,
[tex]\frac{3}{5}=\frac{3\times 4}{5\times 4}=\frac{12}{20}[/tex]
[tex]\frac{1}{4}=\frac{1\times 5}{4\times 5}=\frac{5}{20}[/tex]
[tex]\implies \frac{3}{5}-\frac{1}{4}=\frac{12}{20}-\frac{5}{20}=\frac{7}{20}[/tex]
2) Given problem,
[tex]\frac{5}{6}+\frac{1}{4}[/tex]
LCM(6, 4) = 12,
[tex]\frac{5}{6}=\frac{5\times 2}{6\times 2}=\frac{10}{12}[/tex]
[tex]\frac{1}{4}=\frac{1\times 3}{4\times 3}=\frac{3}{12}[/tex]
[tex]\implies \frac{5}{6}+\frac{1}{4}=\frac{10}{12}+\frac{3}{12}=\frac{13}{12}=1\frac{1}{12}[/tex]
3) ∵ Pizza ate by Manny = [tex]\frac{1}{4}[/tex]
Pizza ate by Frank = [tex]\farc{5}{8}[/tex]
∴ Total pizza eaten = [tex]\frac{1}{4}+\frac{5}{8}[/tex]
LCM(4, 8) = 8,
[tex]\frac{1}{4}=\frac{2}{8}[/tex]
Thus, total pizza eaten = [tex]\frac{2}{8}+\frac{5}{8}=\frac{7}{8}[/tex]