Answer:
Dependent
[tex]x=3-3z[/tex]
[tex]y=-5z-1[/tex]
Step-by-step explanation:
We are given that system of equations
[tex]2x-3y-9z=9[/tex] (Equation I)
[tex]x+3z=3[/tex] ( Equation II)
[tex]-3x+y-4z=-10[/tex] (Equation III)
Equation III multiply by 3 and then add to equation I then we get
[tex]-7x-21z=-21[/tex]
Divided by -7 then we get
[tex]x+3z=3[/tex]
Now , obtained equation subtract from equation II then we get
0=0
Hence, equation II is a linear combination of equation I and equation III.
Therefore, system is dependent because system has infinite solutions.
[tex] x=3-3z[/tex]
Substitute the value of x in equation I then we get
[tex]2(3-3z)-3y-9z=9[/tex]
[tex]6-6z-3y-9z=9[/tex]
[tex]3y=-15z+6-9=-15z-3[/tex]
[tex]y=-5z-1[/tex]