Kyle received the following course grades for 10​ (three-credit) courses during his freshman​ year:

4 comma 4 comma 4 comma 3 comma 3 comma 3 comma 1 comma 1 comma 1 comma 14, 4, 4, 3, 3, 3, 1, 1, 1, 1.

​(a) Find his grade point average by adding the grades and dividing by 10.

​(b) Write down the relative frequency table.

​(c) Find the mean of the relative frequency distribution in part​ (b).

Respuesta :

Answer:

(a) The average grade point is 2.5.

(b) The relative frequency table is show below.

(c) The mean of the relative frequency distribution is 0.3333.

Step-by-step explanation:

The given data set is

4, 4, 4, 3, 3, 3, 1, 1, 1, 1

(a)

The average grade point is

[tex]Average=\frac{\sum x}{n}[/tex]

[tex]Average=\frac{4+4+4+3+3+3+1+1+1+1}{10}[/tex]

[tex]Average=2.5[/tex]

Therefore the average grade point is 2.5.

(b)

[tex]\text{Relative frequency}=\frac{\text{Frequency of number}}{\text{Total frequency}}[/tex]

The relative frequency table is show below:

x                 f                  Relative frequency

4                3                 [tex]\frac{3}{10}=0.3[/tex]

3                3                 [tex]\frac{3}{10}=0.3[/tex]

1                 4                 [tex]\frac{4}{10}=0.4[/tex]

(c)

Mean of the relative frequency distribution is

[tex]Average=\frac{0.3+0.3+0.4}{3}[/tex]

[tex]Average=0.3333[/tex]

Therefore the mean of the relative frequency distribution is 0.3333.

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